Summer 2002


Bailey Challenge


"Die ganze Zahl schuf der liebe Gott, alles Übrige ist Menschenwerk.” This quote is due to the famous German mathematician Leopold Kronecker 1823-1891, and it translates to "God made the integers, all else is the work of man." It is probably more accurate to give God only credit for the positive integers. In the seventh century, the Indian mathematician-astronomer Brahmagupta was one of the first to give the rules for arithmetic involving zero and negative numbers. The two problems for this issue will deal only with the positive integers.




PROBLEM I

Eight squares are arranged as shown in the figure. Two squares are said to be touching if they have at least one vertex in common. In how many different ways can the numbers 1,2,3,4,5,6,7,8 be assigned to the 8 squares so that each square is assigned a different number and that no touching squares contain consecutive numbers?

PROBLEM II

Find a nine digit number N formed from the digits 1, 2, 3, 4 , 5 , 6 , 7, 8 and 9 with the following two properties. a) each digit used exactly once, b) the two digit numbers formed by each pair of consecutive digits in N can be expressed as a product of two single digit numbers.

For example the number 126547983 satisfies condition a). It does not satisfy b) since it contains many consecutive two digit pairs (e.g. 26) that cannot be expressed as a product of two of single digit numbers.

Send your solutions to Herb.Bailey@rose-hulman.edu or to Herb Bailey, Math. Dept., Rose-Hulman, 5500 Wabash Ave., Terre Haute IN 47803.

 

Solution for Previous Issue

You all did well on problems 1 and 2 but some missed problem 3 which was to find the ratio of sphere volume to cube volume for the packing shown. The body diagonal of a box is the line segment joining 'opposite' vertices, and if the box is a cube with sides of length s then the length of the body diagonal is s√3.

Let A and B be one of the pairs of opposite vertices of the cube. Then the body diagonal AB will pass through three of the sphere centers say CA, CO, and CB, where CA is near A, CO is the center of the box and CB is near B. If r is the radius of the spheres and x the distance from A to CA then AB = 4r + 2x. Since x is the length of the body diagonal of a cube with edges of length r then x = r√3, and thus AB = r(4 + 2√3). The side of the cube is then AB/√3 and the required volume ratio is

  




Solvers of the summer problems are listed below:

Alumni:  a. Kelsall, 1940; W. Barrick, 1941; D. Heath, 1943; W. Soudritte, 1943; H. Payne, 1947; J. Hurt, 1948; C. Cook, 1949; A. Junker, 1950; W. Rinker, 1951; C. Hirshfield, 1954; C. Cooper, 1956; J. Chinn, 1956; J. Moser, 1956; A. Sutton, 1956; D. Bailey, 1959; P. DeStefano, 1960; J. Tindall, 1961; J. Snyder, 1962; R. Kraus, 1969; M. Avery, 1976; J. Slupesky, 1979; W. Atterbury, 1980; R. Orr, 1980; K. Moraga, 1981; D. Lyon, 1983; G. Cullen, 1985; M. Lancaster, 1987; C. Abdnour, 1989; B. Burger, 1991; D. Hector, 1992; E. Francher, 1992; K. Fredrick, 1993; J. Atkins, 1994; J. Rott, 1995; T. Adams, 1996; D. Martin, 1998; C. Miesse, 1998; M. Pilcher, 1998; G. Lara, 2000; J. Hochstedler, 2006; D. Rotenberg, 2006; T. Cline, 2006; N. Snyder, 2006; S. Galler, 2006; J. Hanson, 2007

Friends:  L. Gaintner; D. Voltmer; F. Bernard; K. Duffy; G. Elmer; L. Gaintner; J. McGaha; K. Smith

 

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