PH113
Solution to Quiz 5

Tuesday 4/12/16	Name
O205: periods 1, 2
	CM #

The mutual inductance between two coils is M=4.50×10^-3 H.

(a) If the current in coil 1 is changing at a rate of -2.00×10² A/s, what voltage is induced in coil 2? (NO source current in coil 2.)



E2 = -M21 di1 dt = -(4.50×10-3 H) (-2.00×102 A/s) = +0.900 V


(b) If the situation in part (a) is reversed and the changing current in coil 2 is +2.00×10² A/s, what voltage is induced in coil 1 (NO source current in coil 1.)



E1 = -M12 di2 dt = -0.900 V

Note that M₁₂ = M₂₁ º M. No subscripts needed.
(c) If the separation between the coils is increased, will the mutual inductance increase or decrease?
ANS: The mutual inductance decreases.

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On 13 Apr 2016, 17:49.