The figure shows a straight wire segment of length 25.0 cm positioned at an
angle of 120.o with the positive x-axis. The segment carries a constant
current of 2.50 A. There is a constant magnetic field of strength 0.800 T
along the x axis.
(a) Calculate the instantaneous force exerted on the segment.
Give both magnitude and direction.
F
=
IL×B
|F|
=
ILBsinf
=
(2.50 A)(0.250 m)(0.800 T)sin90.0o
=
0.500 N
The force points in the negative z-direction.
(b) The segment is pinned at the origin but is otherwise free to
rotate. If released, what is the axis of rotation and will the segment
rotate CCW or CW?
ANS: The wire would rotate about the x-axis CW.
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version 3.85. On 17 Mar 2016, 19:59.