A 2.50 kg mass is moving along the negative y-axis with a speed of
12.0 m/s. An observer is located on the x-axis at x=+3.00 m. When the
mass is passing through y=+4.00 m, calculate the angular momentum of the
particle relative to the observer. Draw a figure!
L
=
r×p
=
æ è
-3.00 m
^
i
+4.00 m
^
j
ö ø
×
æ è
-12.0 m/s
^
j
ö ø
(2.50 kg)
=
(+90.0 kg·m2/s)
^
k
File translated from
TEX
by
TTH,
version 3.85. On 07 Jan 2016, 18:27.