PH111 - MECHANICS
Solution to Quiz 7

Tuesday 10/13/15	Name
O101: periods 1,2
	CM#

A block of mass m is accelerated (a_x) across a smooth, horizontal surface by a constant force (F) directed and angle q above the floor. The numbers are

m=4.00 kg ax=2.00 m/s2 q = 37.0o F=?

(a) [3 pts] Draw a free body diagram for the block.











(b) [3 pts] Calculate the magnitude of the force F applied to the block.



å Fx = Fcosq = max F = max cosq = (4.00 kg)(2.00 N/kg) cos37.0o = 10.0 N


(c) [4 pts] Calculate the normal force the surface exerts on the block.


å Fy = n-mg+Fsinq = 0 n = mg-Fsinq = (4.00 kg)(9.80 N/kg)sin37.0o = 33.2 N

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On 14 Oct 2015, 10:28.