Homework Solutions

February 6

15.10

d[PH₃] = 0.0048 mol/2.0 L = 0.0024M/s
dt            1 second

rate = -1 d[PH₃] = 1 d[P₄] = 1 d[H₂]
            4 dt            1 dt         6  dt

rate = 0.0006 M/s

d[P₄]/dt = 0.0006 M/s

d[H₂]/dt = 0.0036 M/s

15.11

1 d[NH₃]  =  -1 d[H₂]
2  dt                3 dt

the rate of production of ammonia is 2/3 the rate of consumption of hydrogen.