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Prob 2 |
Be very careful with units here. Do not assume everything works out. |
Some intermediate answers: b2=57.5 μm n=5.17×1025 m-3 |
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1. |
The key is that ideal mixing (at least here) means that the entire mass of each gas fills the entire volume. Also realize that the incoming density is different than the density of that species inside the volume. |
The mass of each species changes exponentially. |
2. |
You will have to integrate here, taking into account that the velocity changes with each r. I would set up an integral with a differential element dA that has r in it. |
Uin = U0/2 |
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2. | A straight forward macroscopic mass and linear momentum application problem. Don't forget that linear momentum has a direction. It may look like there are two streams leaving the plate, but there is in fact only one. V2 is in the radial direction, not the y direction. | |
3. | The solution to this may look trivial to you, but it is of importance to us later on, at least conceptually. | |
4. | Just follow the same method as in 3. and you'll be OK. |
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2. |
Remember that vectors have direction and magnitude, not just magnitude. |
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3. |
"Using what your know about the properties of linear ordinary differential equations" means being able to use l_n_a_r _up_rp_si_t__n. |
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4. |
Assume that disassociated KCL (i.e K+ and Cl- ions) make up the charge carriers in the electrolyte.
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5. |
- For the minimum length, where would the detector be located? Where would this minimum distance between mitochondria plugs occur, then?
Don't forget that the electrophoretic mobility helps you find the velocity relative to the bulk flow. You therefore need an expression for the bulk flow velocity also. - We're using the same concepts here as in part a.
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a.  b. 31.4 mV (-31.4 mV) c.1 mm/s, 59 s |
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1. |
This is an example of how an otherwise complicated heat transfer problem can be reduced to a very simple problem. I suggest you draw two thermal resistors in series and label the voltages (temperatures). Now you need only solve a V1 - V2 = IR problem. You just have T instead of V and Qdot instead of I |
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3. |
For part c, there is more than one correct result, as the correlations are experimental. Parts a and b have just one correct result each. Part d is for a few extra points! |
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1. |
The handout in class is a template for this problem. The one in class was actually harder, as the EOF velocity profile is much simpler, isn't it? |
Nu=constant, where 10<constant<20 (The constant is just one value, but I don't want to give too much away.) |
2. | Take it one step at a time, and all should be well. To get the numbers listed here, fluid properties should be ρ=998 kg/m3, η=0.001 kg/m-s and κ=0.603 W/m-C°. If you use different values, you will get slightly different answers. | - 1.568×10-4 kg/s
- 23.06°C
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3. | Be careful with your areas. Both tubes contribute to the overall heat tranfer area. Also, both tubes contribute to the total mass flowrate for your energy balance. | - Re=141, Nu=3.66
- h=3121 W/m2-°C, Ts=36.01°C
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