CSSE 230
Data Structures and Algorithm Analysis

Homework 4 - 40 points

To Be Turned In

1. (20 points) Weiss Exercise 5.26 [5.20]. Calculate the average-case time complexity of the binary search algorithm. In order to make the calculations simpler, you may assume that N = 2^k - 1 for some integer k ≥ 0, and that all elements are equally likely to be the one we are searching for. Note that the problem only deals with successful searches (where the item we are looking for is actually in the array).

   Hint: For each i, count how many of the array elements will be found after binary search examines exactly i array elements. (For example, the middle element is the only one to be found after examining one array element, and there are two elements that can be found after two probes into the array.) Use a summation to help you find the average.

   Potentially useful fact: Depending on how you work this problem, you may find the following useful:

   
2. (20 points) Checkout the TreePractice project from your SVN repository. Complete them, per the given specifications, and commit your solutions back to the repositories. These are good practice for exams.

For Your Consideration

These problems are for you to think about and convince yourself that you could do them. It would be good practice to actually do them, but you are not required to turn them in.

• (5 points) Problem 6.37[6.22]. You do not have to do this on a computer, but you may do so if it increases your confidence that your code is correct. You must include your code in your submission document. You will (probably) need to refer to the Javadoc documentation of java.util.Map to complete this problem.

• Weiss exercise 6.2 [6.2]. You can just write the code for part (a) out by hand if you wish, but I recommend getting it working in Eclipse and printing out your code. Here is some code that you can use to test your method if you wish:

  public static void main(String[] args) {
    Collection<Collection<String>> a = new ArrayList<Collection<String>>();
    String[][] arrays = {{"abc", "def", "ghi"}, 
                         {"xyz", "uvw", "abc", "abc"}, 
                         {"a", "ab", "abc", "xyz", "abc"}};
    for (String[] sArray : arrays){
      Collection<String> a1 = new ArrayList<String>();
      for (String s: sArray)
        a1.add(s);
      a.add(a1);
    }
    System.out.println(count(a, "abc"));
  } 
  

• Other good problems to think about: 15.1[15.1], 15.3[15.3], 15.5[15.5], 15.9[15.9], 15.10[15.10], 15.12[15.12], 15.13[15.13], 17.3[17.3], 17.4[17.4], 17.5[17.5], 17.6[17.6] , 17.16[17.16]