Table of Contents

Chapter 4: Electricity and Magnetism Experiments

Magnetic Force Between Parallel Currents

References

Crummett and Western Physics: Models and Applications, Sec. 28-2, 29-1,2
Halliday, Resnick, and Walker, Fundamentals of Physics (5th ed.), Sec. 30-2
Tipler, Physics for Scientists and Engineers (3rd ed.), Sec. 25-3

Introduction

Electric current -- moving charge -- creates a magnetic field. In particular, a current in a long straight wire sets up a magnetic field B whose direction at any point is tangent to a circle drawn around the wire. Fig. 1 illustrates this. The direction of B obeys a right-hand rule: if you point the thumb of your right hand along the current direction, its curled fingers indicate the direction of the field lines around the wire. The magnitude of B in this case is given by

(1)

where B is the field at distance d from a wire carrying current I. The constant K depends on the units in which the other quantities are expressed.

It is also true that a current-carrying wire placed in an external magnetic field will experience a force due to the field. If the current is perpendicular to the magnetic field direction, the force is perpendicular to both, and has magnitude

(2)

where L is the length of the wire and I the current in it. The force direction follows from another right-hand rule: if the fingers of the right hand are curled from the direction of I into the direction of B, then the thumb points in the direction of the force.

It follows that two current-carrying wires exert magnetic forces on one another. In Fig. 2, current I1 is the source of a magnetic field at the position of I2; the field exerts a force on I1. (Wire 2 exerts an equal and opposite force on wire 1.) From Equations (1) and (2), the force must be given by

(3)

The SI unit of electric current, the ampere, is DEFINED by saying that the constant K has the value 10-7 N/A2. Thus if the same current I is passed through two parallel wires, the force they exert on one another has the form

with

(4)

In this experiment you will use a current balance to verify the I2 dependence and check the value of the constant C predicted by Equation (4).

Equipment

Procedure

The current balance is sketched in Fig. 3. One of the two wires is part of a frame which balances on a knife-edge. The distance d between the two wires at equilibrium can be adjusted by moving the counterweight. Once a value of d is set, a small weight is placed on the pan and the movement of the balance is observed with an optical-lever arrangement. Current to the wires is then turned on and adjusted until the original balance position is restored; so you have determined how much current in the wires is required to balance a known weight.

CAUTION: It is not hard to damage the knife edges, so consult your lab instructor about proper procedures for adjusting and using this instrument before you get started. The sensitivity of the balance should be adjusted so that the heaviest weight to be used (probably 40 or 50 mg) moves the arm down a distance slightly less than d, so that the wires will not come into contact.

(1) Set up the circuit shown in Fig. 4. Have your instructor check it before you plug it in. Note that the maximum current rating of the power supply is 8 A, and it will be necessary to use currents almost that high in the experi-ment; so you will have to use care in adjusting the current.

(2) Position the laser, as indicated in Fig. 3, so that its beam falls on the wall (after reflecting from the mirror) at a convenient height. Mount a piece of graph paper on the corkboard provided on the wall so that the laser beam falls on it, to use as a scale.

(3) Measure distances L and d and record them, together with your estimates of their uncertainties. d should be set at something on the order of 0.5 cm. (Remember that d is the center-to-center distance between the wires.) Calculate the expected value of C, from Equation (4), and its uncertainty. Record the equilibrium position of the light beam on the scale.

(4) Place a 5 mg weight on the pan, and allow the balance to come to rest at its new equilibrium position. Then turn on the current, and adjust it to restore the original equilibrium position of the balance. Turn the current back to zero, and repeat this procedure several times to obtain an average value of I required to balance the added weight.

Now reverse the current in the wires by turning the power supply to "standby" and exchanging the leads at the power supply terminals; and repeat the entire procedure. Find the overall average value for I from both sets of data.

(5) Increase the mass on the pan in steps of 5 mg and continue repeating procedure (4) until the balancing current reaches nearly 8A.

(6) Increase the equilibrium value of d to roughly twice what it was, and repeat the entire procedure of steps (4) and (5) above.

Analysis

For each value of the weight in the balance pan, calculate the force (mg) between the two currents at balance, and the overall mean value of the balancing current and its standard error.  Make a table of F vs. I for each of the values of d. For each value of d, draw a graph of F vs. I2, and discuss whether your data are consistent with Equation (4). Obtain an experimental value for C from the slope of the graph, together with an estimate of its uncertainty, and compare it to the value calculated from Equation (4). Discuss whether your results agree, within experimental errors, to what is expected from (4).

The reason for reversing the current and averaging the balancing currents you observe in both directions is to cancel out the effects of the earth's magnetic field. Explain how this works.

Faraday's Law

last update 6/96