April 19, 2024
Text Size: T T T
Color Scheme:                         
Language: English | 中文 | All
View All : Main > Courses > Rose-Hulman Institute of Technology > ES203 - Electrical Systems > Week 9 > Problem #2
Keywords:

Power

Power Factor Correction

Problem #2

Three 100 Vrms loads are connected in parallel. Load 1 is a 50 Ω resistor in series with an inductive reactance of 40 Ω. Load 2 absorbs an average power of 500 W at 0.75 lagging power factor. Load 3 absorbs an apparent power of 600 VA at 0.9 lagging power factor. Assume the circuit is operating at 60 Hz. Compute the value of a capacitor that would correct the power factor to 1 if placed in parallel with the loads.

diagram
Need a hint?

solution

Check your result

Additional files available

Video Transcript