Part III. A study of the Feigenbaum diagrams for the logistic family.
3) By using the bifurcation diagram for the logistic map, estimate the value for the period-8 bifurcation point. Try to find the next period doubling bifurcation value after that!
Period 8 appears to be around a8 = 3.545, period-16 is about a16 = 3.565.
4) Suppose a point in an orbit hits very VERY close to a repelling fixed point. It will be repelled, but it may take many iterations before it can escape from that fixed point. Explain, in light of this fact, what causes the dark bands running through the Feigenbaum diagram.
When very close to a fixed point, f(x) is approximately x meaning that the output is close to the input. So, it takes a while to be repelled. Since iterates close to fixed points remain nearby for a while, the dark bands in the Feigenbaum diagram must represent points very close to repelling periodic and fixed points.
7) In light of the result in the last problem, any guesses as to why the Feigenbaum diagram cannot be plotted for a > 4? (You should verify that indeed the Feigenbaum diagram appears empty for all a > 4.)
While there are infinitely many repelling fixed points, most (an uncountable set of points of measure 0 remains!) of the other points diverge. So, even if you are lucky enough to choose a periodic point when a > 4, error in floating point calculations will ultimately take you off into a diverging orbit.