But this solution is not enormously useful when we turn to the problem of how much soda will fit in the resulting box. A twelve-ounce can holds 355 ml, or 355 cubic centimeters. An 8.5 by 11 inch piece of paper is approximately 21.5 by 28 cm.
Input := MetricVol[h_] = h (21.5 - 2h) (28 - 2h);
Input := sol = Solve[MetricVol'[h]==0,h]
Output =
{{h -> 4.01965}, {h -> 12.4803}}
Input := ht = sol[[1,1,2]];
Input := MetricVol[ht]
Output = 1080.02
Input := MetricVol[ht]/355
Output = 3.04231
