4) Use the graph produced in (3) to determine

(a) the maximum beat amplitude and when the maxima occur

From sight, we can estimate the maximum amplitude as approximately equal to 2 and it occurs near t=0, 0.2, 0.4, 0.6, 0.8, and 1. To be sure, we should plot the graphs near our candidate maximum values.

Input := 

Plot[wave1 + wave2, {t, 0, 0.01}]

Output =

-Graphics-

Input := 

wave1 + wave2 /. t -> 0

Output =

2

Input := 

Plot[wave1 + wave2, {t, 0.15, 0.25}]

Output =

-Graphics-

Input := 

wave1 + wave2 /. t -> 0.2

Output =

Cos[48. Pi] + Cos[50. Pi]

Input := 

N[%]

Output =

2.

Due to the periodicity of the waves, if 0 and 0.2 are maxima, so are the remaining values 0.4, 0.6, 0.8, and 1.

(b) based on the result from (a), the beat period is 2/10 seconds.
Remark: The period is the length of time it takes before the wave starts over again. It is easy to confused her because the beats do not look like function if graphed over the unit interval because the oscillations are so frequent.

4) Use the graph produced in (3) to determine

(a) the maximum beat amplitude and when the maxima occur

(b) based on the result from (a), the beat period is 2/10 seconds. Remark: The period is the length of time it takes before the wave starts over again. It is easy to confused her because the beats do not look like function if graphed over the unit interval because the oscillations are so frequent.

(c) the beat frequency is 5 beats/second.

(b) based on the result from (a), the beat period is 2/10 seconds.
Remark: The period is the length of time it takes before the wave starts over again. It is easy to confused her because the beats do not look like function if graphed over the unit interval because the oscillations are so frequent.